Tricky algebra problem

Solve for x in the equation:

(2x + 3)/(x – 2) = (3x + 4)/(x + 1)

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  1. Step 1: Cross Multiply
    Cross multiply to eliminate the fractions:

    (2x + 3)(x + 1) = (3x + 4)(x - 2)

    Step 2: Expand Both Sides
    Expanding the left-hand side:

    2x * x + 2x * 1 + 3 * x + 3 * 1

    2x² + 2x + 3x + 3 = 2x² + 5x + 3

    Expanding the right-hand side:

    3x * x + 3x * (-2) + 4 * x + 4 * (-2)

    3x² - 6x + 4x - 8 = 3x² - 2x - 8

    Step 3: Set the Equation to Zero
    2x² + 5x + 3 = 3x² - 2x - 8

    Subtract everything on the right-hand side from both sides:

    (2x² + 5x + 3) - (3x² - 2x - 8) = 0

    2x² + 5x + 3 - 3x² + 2x + 8 = 0

    -x² + 7x + 11 = 0

    Multiply by -1 to simplify:

    x² - 7x - 11 = 0

    Step 4: Solve Using the Quadratic Formula
    For the equation:

    x² - 7x - 11 = 0

    Use the quadratic formula:

    x = (-(-7) ± √((-7)² - 4(1)(-11))) / (2(1))

    x = (7 ± √(49 + 44)) / 2

    x = (7 ± √93) / 2

    Since √93 ≈ 9.64, we get:

    x = (7 ± 9.64) / 2

    Step 5: Find the Two Possible Values for x
    x = (7 + 9.64) / 2 = 16.64 / 2 = 8.32

    x = (7 - 9.64) / 2 = -2.64 / 2 = -1.32

    Final Answer
    x = 8.32 or x = -1.32

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