Tricky Arithmetic Problem

In a sequence of five consecutive numbers, the sum of the first four numbers is 94. What is the fifth number in the sequence?

Comments

  1. Let's denote the five consecutive numbers as n, n+1, n+2, n+3, n+4.

    The sum of the first four numbers is given as:
    n + (n+1) + (n+2) + (n+3) = 94

    Simplifying this, we get:
    4n + 6 = 94

    Subtract 6 from both sides:
    4n = 88

    Divide by 4:
    n = 22

    So, the numbers are 22, 23, 24, 25, 26.

    The fifth number is:
    n + 4 = 22 + 4 = 26

    The fifth number in the sequence is 26.

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