Tricky Arithmetic Problem

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In a sequence of five consecutive numbers, the sum of the first four numbers is 94. What is the fifth number in the sequence?

Comments

  1. Rithvik9 August 2024 at 08:25

    Let's denote the five consecutive numbers as n, n+1, n+2, n+3, n+4.

    The sum of the first four numbers is given as:
    n + (n+1) + (n+2) + (n+3) = 94

    Simplifying this, we get:
    4n + 6 = 94

    Subtract 6 from both sides:
    4n = 88

    Divide by 4:
    n = 22

    So, the numbers are 22, 23, 24, 25, 26.

    The fifth number is:
    n + 4 = 22 + 4 = 26

    The fifth number in the sequence is 26.

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