Free Online 11+ Maths Tutoring – Open to All

Free Online 11+ Maths Tutoring – Open to All Hi! I’m Rithvik Muthuvelu , a GCSE student at King Edward’s School, Birmingham , and I’m offering free weekly online maths sessions to help students prepare for the 11+ entrance exams . These sessions are open to anyone who wants to improve their maths skills—no school restrictions. What You’ll Get Free weekly online maths classes Focused 11+ preparation : problem-solving, arithmetic, word problems, exam strategies Small-group format for better interaction Ideal for Year 4 and Year 5 students How to Join Weekly Session: Saturdays at 2:00 PM Google Meet Link: https://meet.google.com/nrk-iwmh-gij Contact Email: rithvikmu1@gmail.com If your child is preparing for the 11+ and would like extra support, feel free to join the class or get in touch. Looking forward to helping more students learn and grow! — Rithvik Muthuvelu  

The Train Journey Conundrum

A train leaves Station A at 9:00 AM and travels towards Station B at a constant speed of 60 miles per hour. At the same time, another train leaves Station B and travels towards Station A at a constant speed of 40 miles per hour. If the distance between Station A and Station B is 200 miles, at what time will the two trains meet?

Comments

  1. To find the time when the two trains meet, we need to determine the combined speed of both trains and the total distance they need to cover.

    The combined speed of the two trains is:
    60 miles per hour + 40 miles per hour = 100 miles per hour

    The distance between Station A and Station B is:
    200 miles

    To find the time taken to meet, we use the formula:
    Time = Distance / Speed

    Plugging in the numbers:
    Time = 200 miles / 100 miles per hour = 2 hours

    The trains will meet 2 hours after they start, which is at:

    9:00 AM + 2 hours = 11:00 AM

    Therefore, the two trains will meet at 11:00 AM.

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