Town A and Town B
A train travels from Town A to Town B at a constant speed of 80 kilometres per hour (km/h). On the return journey from Town B to Town A, the train travels at a constant speed of 100 km/h. The total travel time for the round trip is 6 hours. How far is Town A from Town B?
Let's call the distance between Town A and Town B "D" kilometers.
ReplyDeleteFor the trip from Town A to Town B, the train travels at 80 km/h. So, the time taken for this trip is D/80 hours.
For the return trip from Town B to Town A, the train travels at 100 km/h. The time taken for this trip is D/100 hours.
The total time for both trips is 6 hours. So, we can write the equation:
D/80 + D/100 = 6
To solve for D, first find a common denominator for the fractions, which would be 400 (since 400 is the least common multiple of 80 and 100). This gives us:
5D/400 + 4D/400 = 6
Combining the fractions, we get:
9D/400 = 6
Now, solve for D:
9D = 6 × 400
9D = 2400
Divide both sides by 9:
D = 2400 / 9
D ≈ 266.67
So, the distance between Town A and Town B is approximately 266.67 kilometers.