Town A and Town B

A train travels from Town A to Town B at a constant speed of 80 kilometres per hour (km/h). On the return journey from Town B to Town A, the train travels at a constant speed of 100 km/h. The total travel time for the round trip is 6 hours. How far is Town A from Town B?

Comments

  1. Let's call the distance between Town A and Town B "D" kilometers.

    For the trip from Town A to Town B, the train travels at 80 km/h. So, the time taken for this trip is D/80 hours.

    For the return trip from Town B to Town A, the train travels at 100 km/h. The time taken for this trip is D/100 hours.

    The total time for both trips is 6 hours. So, we can write the equation:

    D/80 + D/100 = 6

    To solve for D, first find a common denominator for the fractions, which would be 400 (since 400 is the least common multiple of 80 and 100). This gives us:

    5D/400 + 4D/400 = 6

    Combining the fractions, we get:

    9D/400 = 6

    Now, solve for D:

    9D = 6 × 400
    9D = 2400

    Divide both sides by 9:

    D = 2400 / 9
    D ≈ 266.67

    So, the distance between Town A and Town B is approximately 266.67 kilometers.

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