Sum of prime divisors

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 What is the sum of the distinct prime integer divisors of 2016?

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  1. Anonymous2 December 2021 at 09:09

    The prime factorization is 2016=2^5 * 3^2 * 7. Since the problem is only asking us for the distinct prime factors, we have 2,3,7. Their desired sum is then 12

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