Piles
There are twenty gifts stacked up into four piles.
The first pile has 3 less than the second pile.
The second pile has two more than the third pile.
The fourth pile has twice as many as the second pile.
How many gifts are in each pile?
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Using these we can make equations:
ReplyDeletea = first
b = second
c = third
d = fourth
b = 3 + a
b = c + 2
d = 2b
3 + a = c + 2
a = c - 1
b = c + 2
c = c
d = 2c + 4
c - 1 + c + 2 + c + 2c + 4 = 20
5c + 5 = 20
5c = 15
a = 2
b = 5
c = 3
d = 10